1im sorry 'x' here is the distance from the left end of the vessel..
i made up this question last nite,.,...so forgive me for languge error.....
but i hopw u get the essence of the question
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21http://targetiit.com/iit_jee_forum/posts/help_crack_da_solution_phy_2945.html
chk dis, it will help!
24nahin yaar.......i am only intrested in knowing shape of fluid.......
i know theoritical job......
i am trying above experiment with a bucket in my bathroom.....[3][3]but cant conclude anything except for my wet clothes[9][9][9]
1i did it jus roughly...dont blame me for wrong results...
on the left side of the symettry line, we have depth of the water surface 'h' as a function of 'x' as
h=\frac{x}{2g}[(\omega _{1}^{2}+\omega _{2}^{2})x-2\omega _{2}^{2}R]
ill do it properly now...
24ok gordo..u are doing theory job...thats good.........
but i wanted to know how fluid shape will look like........surely it will be irregular.....but rough idea.....
1luk trusting that what i have put down is even roughly rite,
we have h=0 at x=2Rw22 /(w12 +w22)
now the cases that uve put down,
if w1>w2
we wud have this point where it comes back to normal height at a point in the left side of the symettry line of the container..
if w1=w2
we have this happening on the symettry line itself, i mean the liquid surface wud first go down and come up again at the symettry line itself...
for the third case i need to reluk at the trajectory on the right side of the symettry line...
9i have a strong feeling motion of container doesnt affect shape in any way as long as liquid bulk has a particular ω
1yes i completely agree with celestine
unless the liquid is viscous there will be no effect in motion