Let the spring be stretched by x0 and the block be displaced by x.
If the restoring force on the block be Fr.
Note, 2x0=x ... (i)
2Fr = kx0
x0 = 2Frk
Put in (i),
4Frk=x
4mω2x = kx
ω = 12√(k/m)
Time period = 4\pi \sqrt{\frac{m}{k}}
In the given figure, the spring has spring constant k . The pulley is light and smooth , the spring and the string are light. The suspended block has a mass m. If the block is slightly displaced from its equilibrium position and then released.Find the time period of its vertical oscillation.
just find by how much does the spring stretches when you displace the mass by x
Let the spring be stretched by x0 and the block be displaced by x.
If the restoring force on the block be Fr.
Note, 2x0=x ... (i)
2Fr = kx0
x0 = 2Frk
Put in (i),
4Frk=x
4mω2x = kx
ω = 12√(k/m)
Time period = 4\pi \sqrt{\frac{m}{k}}
Ohh thanks Ashish i did everything right except equating 2fr=kxo i equated
fr=kxo