T1 is the time period of simple pendulum.The point of suspension moves vertically upwards according to y=kt2,where k=1m/s2.New time period is T2,then T21T22=
A. 4/5
B. 6/5
C. 5/6
D. 1
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UP 0 DOWN 0 0 1
1 Answers
11Ans) Y = K t 2
Acceleration at the point of suspension,
a = d 2y / dt2 = 2 K
Therefore, a = 2 m/s2 [as K = 1 m/s2]
Since, T = 2 ∩ √(L / g eff)
Therefore, T 1 = 2∩ √ (L /10)
Similarily, T 2 = 2∩ √[L / (10 +2)] = 2∩ √(L/12)
Therefore, T1 2 / T2 2 = 6/5
