1y=\frac{1}{(1+x)^{2}} at t=0
At x=0 , y = 1 = ymax
Again
y=\frac{1}{1+(x-1)^{2}} at t = 2 sec
At x = 1m, y=1 =ymax
These two equation show that in 2sec wave pulse has moved a distance of 1 m.
so speed of wave pulse : v= 1/2 = 0.5 m/sec
The amplitude of a wave disturbance propogation in the +ve X direction is given by y=1/(1+x^2) at t=0 and by y=1/[1+(x-1)^2] at t=2 sec. The velocity of wave is
-
UP 0 DOWN 0 0 2
2 Answers
1
1rom the eqution displacement in x direction is 1m in 2s so
v=0.5m/s