determine d period of oscilations of mercury of mass m=200g poured into d bent tube whose right arm forms an angle of @=30 degree wid d vertical . d cross sectional area of d tube is S=.5cm^2 d viscosity is neglcted
1let initial perpendicular height be 'l
now, just imagine that u took out 'x' units of perpendicular mercury from left side,
& pour this 'x' length on right side, it will measure x along the right tube,
now a total of x/(sinθ+cosθ)will contribute for the excess force towards equilibrium position,
nowfind excess forxe in terms of 'x' , it will be directly proportional to x,, ie SHM
did u understand the hint or should i post diagram???????????
1na ramkumar .......
and dimensions itz bombarding me .....and getttin adsorbd ......
plez post ur dia
11dimensions, u r bamboozling me with ur bold reply([6]). Can u pls post ur diagram so that mortals like me find it easier?
1restoring force will only be due to x(1+secθ) length,for right hand tube
did it helped?????
here's the diagram, hope it might help.