1someone try yaar
1. A SIMPLE HARMONIC OSCILLATOR HAS AMPLITUDE A ,ANGULAR VELOCITY w AND MASS m ,THEN AVERAGE ENERGY IN ONE TIME PERIOD IS:
a) 14 mw2A2 b)12 mw2A2 c) mw2A2 d) 0.
2. A PARTICLE OF MASS m IS OSCILLATING NEAR THE MINIMUM OF OF THE PARABOLIC PATH x2=4ay , FIND THE FREQUENCY OF SMALL OSCILLATIONS.
3.THERE IS A ROD OF LENGTH l AND MASS m .ONE END IS HINGED TO CEILING. FIND THE PERIOD OF SMALL OSCILLATION.
4.A CLOCK PENDULUM IS ADJUSTED FOR GIVING CORRECT TIME IN PATNA.THIS CLOCK PENDULUM ALSO GIVES CORRECT TIME IN
a)DELHI b)KOTA c)HYDERABAD d)NONE OF THESE
5.THERE IS CLOCK WHICH GIVES CORRECT TIME AT 200 C IS SUBJECTED TO 400 C.THE COEFFICIENT OF LINEAR EXPANSION OF PENDULUM IS 12 * 10-6 per 0 C ,HOW MUCH IS THE GAIN OR LOSS IN TIME.
a)10.3 sec/day b)19 sec/day c)5.5 sec/day d)6.8 sec/day
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9 Answers
1man except the 2nd sum all r easy actually 2 easy
1) simple 1/2ka^2 as total enrgy is constant
3) t=2pie √I/mgl where i is abt the pnt of suspension and l is the disnace of the pnt from cxom
4)this question relates bt effective value of g n it will be the same for the places on the sme latitude (simple geo) so none of dese (maybe im wrong i hv a record of getting LOW marks in geo)
5) its a simple math case
11K.E = 12 m w 2 ( a 2 - y 2 )
P.E = 12 m w 2 y 2
so average energy = (K.E + P.E) /2
====>14 m w2 a2
(a)
i am not too sure though..
1but if i am not wrong isnt the total enrgy constant through out the motion i dont think there r exceptions 2 this rule
1friend its from arihant , ialso think it should be b) but they have avereged potential energy and got a).