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P.S the springs are attached to string
and x=a

6 Answers

\omega =\sqrt\frac{3(k_{1}+k_{2})}{m}??

consiering that x=a=L/2

bcz upper length is L/2 in d fig ..

dimensions itself are wrong @ joker

btw donno why did i take x=L/2 [16]

T=\pi \sqrt{\frac{4I}{k_{1}L^{2}}}+\pi \sqrt{\frac{I}{k_{2}a^{2}}} ??

btw realised da mistake dat i made initially [4]

184 views , 3 replies , badi na insafi hai !!! [3]

T=\pi \sqrt{\frac{I}{K_{2}a^{2}}}+\pi \sqrt{\frac{4I}{K_{1}L^{2}}}

i hav written (T₁+T₂)/2

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