SHM questions ....

1) The motion of a particle varies with time as y=A(sinwt+coswt)
Then the motion is an SHM whose amplitude is
a)A
b)2A
c)A/2

2)A particle undergoes SHM with time period T. The time taken to complete 3/8 the of the oscillation is
a)5/8T
b)5/12T
c)7/12T
d)3/8T

please tell me how u got the answer. ...

3 Answers

wat bout âˆš2A

2nd ans is (c)

3/b of oscillation means y=-A/2

=> -A/2=A sinÏ‰t

=> sinÏ‰t=-1/2

=> Ï‰t=(7/12) 2Ï€

=> t=(7/12) 2Ï€ (T/2Ï€)

therefore, t=(7/12)T......ans is (c)

and yeah first ans will be Aâˆš2

this is because max value for (sinÏ‰t+cosÏ‰t) is âˆš2.....

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