no 1st answer is vmax
that is sure as the time taken for a particle to assume vel vmax twice is the time period
1) The time period of a particle in SHM is equal to the smallest time between the particle acquiring a particular velocity v. The value of v is
(a) vmax
(b) 0
(c) between 0 and vmax
(i think this value can be anything)
2) Two small balls, each of mass m are connected by a light rigid rod of length L. The system is suspended from its centre by a thin wire of torsional constant k. The rod is rotated about the wire by an angle θ0 and released. Find the tension in the rod as the system passes through the men position.
(i m getting the answer without the factor "mg". But what role has gravity to play??)
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11 Answers
for q 2 i also had this doubt when i solved this one ,
see the rod will slightly be bent , it cant be be perfectly horizontal.
so horizontal comp of T u calculated, and vertical comp balances weight
no 1st answer is vmax
that is sure as the time taken for a particle to assume vel vmax twice is the time period
still i m not getting (1)
suppose particle starts from extreme....then the time when its vel is zero for the 2nd time is the time period....
in 1, its gonna be c. the velocity can b anything btw 0 nd vmax (including vmax and 0).
for case 1 ,i think it can be anything between 0 to V (max), excluding zero..because wen the particle is having vel. 0 for the smallest time then T=(1/2) time period...and as velocity is a vector, whenever the particle is having same velocity vector after the smallest time,it is time period...but incase of zero velocity,it is a null vector,then the time when its vel is zero for the 2nd time is the time period....(taken from Euclid)...:P
so it can be anything between 0 to v max.....excluding zero.....
it wil be (a) vmax
this is bcz all other velocities are obtained by the particle twice within a time period
hey i got it.... the ans to my question will be 0 or vmax... but the actual question is given as velocity vector which can be attained only once and hence it has to be vmax (i was wandering about speed)
ne wez thank u all for ur cooperation