SHM.........

yaar jab hum thoda sa displace karenge to velocity kahan se aaegi

@ tapan........stick to one method and master that...if u r comfortable with force method and have already done this question by that method dont try to do by other method.....
at least at this point of time....

Dude, i m not dat gr8 at these Time period Questns...........

So if i knoe ENERGie methd than I can use it..........

If u knoe how to use energie methd in dis un pl telll

Sum1 pl. help wid energie methd

bichhara tapan ghante ka pooch raha hai
bhai ki help to kar do
i htink #4 is sufficient but he needs more[1]

ha ha thnx 4 ppropaganda.......

I want to knoe the Applctn of Energie methd in such situations is liye pura methd mang raha huun...........

tapan bhai mujhe energy method bilkul nahin aata...........isliye sorry i cant help u..........

let me try:

equilibrium position is T=mg and 2T = kx
so, x = 2mg/k... = y (say)

if we displace the block by distance x downwards, then spring extends x/2 downwards.

So, mv²/2 + k(x/2+y)²/2 - mgx = const.
taking derivative wrt time,

mva + kxv/4 + kyv/2 - mgv = 0
==> ma + kx/4 + ky/2 - mg = 0
==> ma + kx/4 + k*2mg/2k - mg = 0
==> ma = -(k/4)x
==> a = -(k/4m)x
==> ω = √k/4m

So T = 2Î √4m/k
= 4Î √m/k

@manipal....
arey yaar hamain acceleration find out karni hai na..toh a-g bhi toh uski net acceleration hi toh hai......

aur agar usme problem a rahi ho toh.... asish ne jo kiya hai woh bhi thik hai....