SHM.........

hoW TO DO THIS UN BY ENERGY METHD ???

maine thoda kiya par aage [7]

16 Answers

11
Mani Pal Singh ·

AB ISSM MEIN AAGE KYA KARNA HAI
ISN'T THE ANSWER (B)

21
tapanmast Vora ·

IT IS B..........

WOH JO BOTTOM RITE main likha hai wo step GALAT hai, as i hav not differetiated x in that........ th one on the left is crrct ..........

11
Mani Pal Singh ·

yaar jab hum thoda sa displace karenge to velocity kahan se aaegi

21
tapanmast Vora ·

[12] [7]

SirJEE ko puchhte hain......

24
eureka123 ·

@ tapan........stick to one method and master that...if u r comfortable with force method and have already done this question by that method dont try to do by other method.....
at least at this point of time....

21
tapanmast Vora ·

Dude, i m not dat gr8 at these Time period Questns...........

So if i knoe ENERGie methd than I can use it..........

If u knoe how to use energie methd in dis un pl telll

21
tapanmast Vora ·

Sum1 pl. help wid energie methd

11
Mani Pal Singh ·

bichhara tapan ghante ka pooch raha hai
bhai ki help to kar do
i htink #4 is sufficient but he needs more[1]

21
tapanmast Vora ·

ha ha thnx 4 ppropaganda.......

I want to knoe the Applctn of Energie methd in such situations is liye pura methd mang raha huun...........

24
eureka123 ·

tapan bhai mujhe energy method bilkul nahin aata...........isliye sorry i cant help u..........

1
prateek punj ·

mg(H-x) + ky2/2 +mv2/2 =constant.....

y=x/2...by constraint.....

where x= displacement of mass m
y= displacement of pulley= extension in spring.....

differentiating.......

-mgv + kxv/4 +mva = 0...

where v=velocity and a =acceleration....

net acceleration....

a-g = anet = -kx/4m.....

therefore, time period = 4Π√m/k

21
tapanmast Vora ·

OH K!!! THNX [1]

i had missed the KE term......

11
Mani Pal Singh ·

a-g = anet = -kx/4m.....

therefore, time period = 4Π√m/k

yeh samjha de bhai!!!!!!!!!

106
Asish Mahapatra ·

let me try:

equilibrium position is T=mg and 2T = kx
so, x = 2mg/k... = y (say)

if we displace the block by distance x downwards, then spring extends x/2 downwards.

So, mv2/2 + k(x/2+y)2/2 - mgx = const.
taking derivative wrt time,

mva + kxv/4 + kyv/2 - mgv = 0
==> ma + kx/4 + ky/2 - mg = 0
==> ma + kx/4 + k*2mg/2k - mg = 0
==> ma = -(k/4)x
==> a = -(k/4m)x
==> ω = √k/4m

So T = 2Î √4m/k
= 4Î √m/k

106
Asish Mahapatra ·

sry prateek hadnt seen u had posted

1
prateek punj ·

@manipal....
arey yaar hamain acceleration find out karni hai na..toh a-g bhi toh uski net acceleration hi toh hai......

aur agar usme problem a rahi ho toh.... asish ne jo kiya hai woh bhi thik hai....

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