1den....
a smooth ring P of mass m can slide on a fixed horizontal rod....a string tied to the ring passes over a fixed pulley and carries a block of mass m/2 as shown....at an instant the string between the ring and the pulley makes an angle 60degrees .... with the rod....INITIAL acceleration of the ring is
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15 Answers
62this is one of the tough looking simple problems :)
the fbd of the ring is to be drawn
Hint: there is no rotational mechanics involved :)
1@aarthi
T varies wit theta, u hav to use ma=Tcos(theta)
and in ur eqn it is ma/2 n not ma
1I am gettin g/18....Is it rite??[12][12][7][7]
[ I hav doubt in one part- My aalternative answer is g/10 hehe]
1
From the figure,
mg/2 -T =macos60°/2
T = macos60°
Hence,
mg/2=3macos60°/2
a=2g/3
Do U hav da answer[7][7][33]
62kalyan.. check this one.. your constraint equation is incorrect!