3eureka i am getting that interaction force is not depend on a
This is Season2 of "Some good revision problems"
which was completed succesfully here last year
http://targetiit.com/iit-jee-forum/posts/some-good-revision-problems-2579.html
All the rules are same as mentioned there.....
We will do +2 Physics first...Chapterwise....
Here is first question
Q1Two mutually perpendicular long straight conductors carrying distributed charges of linear charge densities λ1 and λ2 are positioned at distance a from each other.how does interaction between rods depend on a
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14 Answers
3let the rod perpendicular to plane be A and the other be B.
Consider a dq charge on B now the field it experience due to A is
E=Kλ1/x (x is the radial distance of the dq charge from A)
The interaction force =dqE=kxdθλ1λ2/x=> force =Kλ1λ2π
24Pity no one is taking inititative to solve the question........
I fear it this thread might be lost...............unlike very succesful previous one......
1oh sorry...overlooked #3...
i'll check again...i was so sure that i did it correctly!!
24right answer by karna...
here is next
Q2 A system consists of a thin charged wire ring of radius r and a very long uniformly charged wire oriented along the axis of ring with one ends coinciding with the centre of ring.The total charge on rign is q, and linear charge density of straight wire is λ.Evaluate interaction fore between wire and ring
4F axial = ∫ [kλ / R] dQ = kQλ/r
Fradial - > gets cancelled out due to symmetry
So Ans is F = kQλ/R
11Conservation of angular momentum
dm*v*r = Iω
I =MR2/2
ω = 2dm*v/M*r