Yesterday Philip was frustrated at the lack of gud problems...I am posting some for everyones practice..........2009 aspirants should solve them and put up solutions here for 2010 students to learn.............
Some might be easy.......but all are conceptual[1][1].....
Q1 A uniform rod of length 2a and mass m is rotating in horz plane about a smooth fixed pivot through the centre of rod with a constant angular velocity w rad/s.A particle of same mass moving with speed aw/4 opposite t orod strikes one end of the rod perpendicular to it.If e=1/2,calculate angular velocity of rod immediately after collision.
If anyone has problem with my initiative he/she is free to express his/her views...........i wont feel bad at all and i will stop this work at that moment only..[1][1][1][1]
106is it 9w/32 rad/s in the same direction as before?
btw. its a gud initiative.glad if such things wud come for organic too.
thx dude.
24Q2 A scale is placed in tilted position in vertical plane.The lower end of scale touches the groound.The surface has friction.The scale now falls in such a way that the loweer end is at rest.The other end has velocity of 2m/s when it hits the ground.Find out angular velocity of scale assuming length =1m.Also find velocity of CM of scale.
24let others also try it...........if u r sure then u may post ur solution here using hide feature..........
I will post answer one day after posting the question so that everyone gets ample time to solve it.......[1][1]
3sorry for poosr handritin............and yaar in q2 is the bottom fixed??????
3and yaar when to find angular velocity when it is just release or in the end??????
3@may be for iit(his post is now deleted) ... if its in the end then the angular velocity will simply be 2/1!!!!!! as the other end becomes the iaor as it is at rest!!!!!!and com will hav velocity 1m/s!!!
3Hey..iitimcomin....its given the initial velocity of the body of same mass is 'opposite' to that of the rod...so inital angular momentum will neative sign before the second term...othrwise i think the concept is correct ...
3Thermal physics: Thermal expansion of solids, liquids and gases; Calorimetry, latent heat; Heat conduction in one dimension; Elementary concepts of convection and radiation; Newton's law of cooling; Ideal gas laws; Specific heats (Cv and Cp for monatomic and diatomic gases); Isothermal and adiabatic processes, bulk modulus of gases; Equivalence of heat and work; First law of thermodynamics and its applications (only for ideal gases). Blackbody radiation: absorptive and emissive powers; Kirchhoff's law, Wien's displacement law, Stefan's law.
1nice handwriting iitimcoming......[1]...1 of my friend had handwriting like u .....
24when its going to strike dear.........its very easy.....i hope u can wrap it up......[1]
24and what happened to Q3???????u wanted a thermo question....so i posted it........do solve it,......[1]
3ΔU(A TO B)=0
ΔU(B TO C)=nCv(1V2/2R - 3V2/2R)....................
V2 = 2(600R)(1/3).................
ΔU(d TO a)=nCv(5V1/2R - 2V1/2R)
V1=2(600R)(1/5)...................
net ΔU = 0............
ΔU(c to d) = 0 - ΔU(A TO B) - ΔU(b TO c) - ΔU(d TO a).................
Q=W + ΔU(c to d),,,,,,,,,,,,,,,,
THUS EVERTTHIN SOLVED!!!!!!
24yup u r rite iit.........post the solution for Q2 here for others...as 1 day gone.......[1][1]
3if its in the end then the angular velocity will simply be 2/1!!!!!! as the other end becomes the iaor as it is at rest!!!!!!and com will hav velocity 1m/s!!!
(same as in #8)
24all 3 have been solved so here is fourth one.....
maybe a sitter.....[3]
Q4 A disc has velocity v and angular velocity w.It strikes a scale of same mass and length 2R at the edge and then sticks to the scale such that scale rotates along extension of radius.Both lie on horz frictionless surface/.Can we apply conservation of angular momentum here?If so write down the eqn.
24thats true......write the eqn then.....i knew it was very easy.....gave it in hurry
3since its not pivoted we can conserve ang. mom about any point!!!!!!!!!!!!!
so lets concider the center of the rod!!!!!!!!!!!!!!!!
mvR + I(com)W = [I(com rod)+I(com disc)+mR^2]W/ + mw/R..........
