Some good revision problems

Yesterday Philip was frustrated at the lack of gud problems...I am posting some for everyones practice..........2009 aspirants should solve them and put up solutions here for 2010 students to learn.............

Some might be easy.......but all are conceptual[1][1].....

Q1 A uniform rod of length 2a and mass m is rotating in horz plane about a smooth fixed pivot through the centre of rod with a constant angular velocity w rad/s.A particle of same mass moving with speed aw/4 opposite t orod strikes one end of the rod perpendicular to it.If e=1/2,calculate angular velocity of rod immediately after collision.

If anyone has problem with my initiative he/she is free to express his/her views...........i wont feel bad at all and i will stop this work at that moment only..[1][1][1][1]

144 Answers

24
eureka123 ·

@ asish what is R in Q15???????u have used it in 2 places..........

106
Asish Mahapatra ·

edited that

24
eureka123 ·

last mein jo R hai vo resultant force hai naa???????

106
Asish Mahapatra ·

haan..

24
eureka123 ·

how this .......mv = 2mVcom

24
eureka123 ·

and Q14 ans is l/2

106
Asish Mahapatra ·

okk sry posting again....

24
eureka123 ·

my friend it is clearly written elastic collison...........

24
eureka123 ·

106
Asish Mahapatra ·

CONSERVING LIN. MOMENTUM
mv = mv1 + mv2 ... (i)

where v1 = vel of ball after collision and v2 is vel of com of rod after collision

CONSERVING ANG. MOMENTUM
mvR = mv1R + mL2ω/12 ... (ii)

R is dist of point of collision from COM of rod..

COR EQUATION
v2 + ωR - v1 = ev ... (iii)

for vel of A to be at rest immediately after collision,
v2 = ω(L/6 + R) .. (iv)

as collision is elastic e=1

24
eureka123 ·

pichla post to delete kar de fir,,,taki confusion naa ho

24
eureka123 ·

why is this thread dead?????????????????????????[11][11]

there are a lot of unanswered questions.................try them...........[1][1]

3
iitimcomin ·

helllloooooo eureka .............. kya haal hai ....... longgggtime .............

24
eureka123 ·

ya gud work,............no one noticed.q17 was jee problem.....[3][3]

24
eureka123 ·

but ur constraint is a bit wrong.,,........[2]recheck it.....

3
iitimcomin ·

i feel its right ................ the mass M will move over an arc ............and the velocity of the mass m is the ""net""(horizontal + vertical) velocity of the mass M

24
eureka123 ·

boards are over...........so renewing this thread.........hope to see some participation here........

Q18 A particle of mass 2m is projectedat angle 45 with horz with a velocity 20√2 m/s .After 1 second explosion takes place and particle is broken into 2 equal pieces.As a result of
explosion one particle comes to rest.Find max height gained by other part.

24
eureka123 ·

Q19 Determine the natural frequency of vibration of 100N disc.Assume no slipping.(very eassy)

24
eureka123 ·

Q20 one fourth length of uniform rod of mass m and length l is placed on rough horz surface and is held stationary in horz position by a light thread.the thread is then burnt and rod starts rotating about edge.Find angle b/w rod and the horz when it is about to slide on edge.coeffecint of restitution=μ

1
skygirl ·

19. t= 2piroot(k/m) bus :)

3
iitimcomin ·

ah.,............eureka paaji kya haal hai..............

3
iitimcomin ·

3
iitimcomin ·

sky u seem to have ignored friction.....................how did u get k/m..........im gettin rt2k/3m as w .................see the bottom part of above page.......tellme if u find anythin rong........

3
iitimcomin ·

3
iitimcomin ·

yaar eureka it shud be coeff of friction khan se restitution aaya???????????????must be a typo.........u musta been 1/2 asleep ...while typin.................

3
iitimcomin ·

are these the answers????????????????????

24
eureka123 ·

good work....but ans 18 is wrong.....[2][2]

24
eureka123 ·

posting more........
Q21

Disc is pivoted at centre
pt . indicated

24
eureka123 ·

Q22

3
iitimcomin ·

u mean impulse at pivot???????????

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