1Yes both debo and akari are right.
First there is static case : kx = mg
and then condition of equilibrium....NOT REST.
An object is attached to a vertical spring and slowly lowered to its equilirium position.this streches the spring by an amount d.if d same object attachd 2 d same spring is permitted to fall instead,through wat distance does it stretch the spring??pls help...
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3 Answers
19in the first case, there is no gain of kinetic energy of the body whereas it is gainable in the second case !
1debo is right
first case
kx =mg
second case
(1/2) kx2 =mgx
so it will fall a distance of
2d
1