stones

a stone is dropped into a well 80m deep & impact of sound is heard after 4.25 s if g=10m/s2 d vel of sound in air is

1 Answers

u= 0
s= 80
let 't' be time taken for stone to reach the bottom of the well.

80= gt²/2

t= âˆš(160/10)
t= 4s

time taken by sound to reach the opening of the well. = 4.25-4=0.25s

speed of sound = 80/0.25 = 320m/s

edited I didn't see the other questions were the same.

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