a particle experiences constant acceleration for 6 secs after starting fom rest.
it travels d1 in first 2 secs
it travels d2 in next 2 secs
it travels d3 in last 2 secs
then,
d1:d2:d3 = ???
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4 Answers
106d1 = a*4/2 = 2a
d2 = d(in 4 sec) - d1 = a*16/2 - 2a = 6a
d3 = d(in 6 sec) - d(in 4 sec) = a*36/2 - 8a = 10a
So, d1:d2:d3 = 1:3:5
no question is stupid btw
1dont worry sky.........i hav posted more stupid questions than this one..................so this isnt d stupidest hehehe