If the coeff of friction were 0.05, a=-0.5ms-2
Hence,
v=u+at
0=4-(0.5)t
So, t=8s
[339]
The velocity time graph of the figure shows the motion of a block of mass 1 kg which is given an initial push at t=0 along a horizontal table
Show that
(a) The coeff of friction b/w the block and the table is 0.1
(b) If the table was half of it's present eoughness, the time taken by the block to complete the journey is 8 sec.
a) first see that the retardation is given by 1m/s^2 from the graph
which is equal to mu.g
thus the answer :)
If the coeff of friction were 0.05, a=-0.5ms-2
Hence,
v=u+at
0=4-(0.5)t
So, t=8s
[339]
This is not related to this question..
@ osama....why are u posting silly names for ur threads like AK47 and terrorism ??
This increases trouble in finding the questions from search option..
Also thread names like this don't look decent at all on an educative site...
Plz dont repeat these things in future..[16][16]
I hope u get my point[1]