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A block with a square base measuring a x a & height h is placed on an inclined plane of angle \Theta . The coefficient of friction is \mu
The angle of the incline is gradually increased. The block will::
a) topple before sliding if \mu > ah
b) topple before sliding if \mu < ah
c) slide before toppling if \mu > ah
d) slide before toppling if \mu < ah
plzzzz in this problem explain from the basics....
plz explain why the normal reaction shifts , due to which torque etc....!!!!!
fig given is
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UP 0 DOWN 0 1 4
4 Answers
Tapas Gandhi
·2010-02-24 22:17:09
A,D
f=μmgcosθ
N=mgcosθ
Torque due to f:
μmgcosθh
Torque due to N: (to counter balance torque due to f, N shifts towards left)
mgcosθa
Toppling:
μmgcosθh>mgcosθa
μ> a/h
Sliding:
μ<a/h