the jokers first query......though may be easy for many but this joker still has doubt.....

find the time period of small oscillation of mass m abt its mean pos....assume ideal conditons

7 Answers

1
xYz ·

1
thejoker ·

sorry bro but thats not the answer.........i also did the same way as u did....but that really not the answer.........answer is 2pie(m(k1 +4k2)/(k1k2))^ .5 and in ur answer in w where m has gone....i was getting same as urs but one m was multiplied in numerator with k1k2 within the root.....

1
thejoker ·

oh thanx dear

1
thejoker ·

yeah nishant sir plzzzz help.....

1
thejoker ·

somebody plzz help.....

1
thejoker ·

Why So Serious abt this question......come on guys help.....

62
Lokesh Verma ·

2k1x1=k2x2

are you sure?

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