the jokers first query......though may be easy for many but this joker still has doubt.....

BITSAT 2015 Guidance › Mechanics questions › the jokers first query......though may be easy for many but this joker still has doubt.....

find the time period of small oscillation of mass m abt its mean pos....assume ideal conditons

#Physics #Mechanics

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7 Answers

1

xYz ·2009-10-09 21:34:32

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1

thejoker ·2009-10-09 21:47:53

sorry bro but thats not the answer.........i also did the same way as u did....but that really not the answer.........answer is 2pie(m(k1 +4k2)/(k1k2))^ .5 and in ur answer in w where m has gone....i was getting same as urs but one m was multiplied in numerator with k1k2 within the root.....

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thejoker ·2009-10-09 22:11:11

oh thanx dear

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thejoker ·2009-10-09 22:13:32

yeah nishant sir plzzzz help.....

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thejoker ·2009-10-09 22:40:28

somebody plzz help.....

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thejoker ·2009-10-09 22:48:09

Why So Serious abt this question......come on guys help.....

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62

Lokesh Verma ·2009-10-10 01:32:58

2k1x1=k2x2

are you sure?

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Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

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