Taking theta = @
2 T sin @ = F
T cos @ = m a
Therefore, 2 tan @ = F / ma
since tan @ = √(l2 - x2)x
Therefore, a = F / 2m x √ (l2 - x2)
Taking theta = @
2 T sin @ = F
T cos @ = m a
Therefore, 2 tan @ = F / ma
since tan @ = √(l2 - x2)x
Therefore, a = F / 2m x √ (l2 - x2)