23question is correct
it means Force reqd when it is in horizontal direction = n times the force required when it is applied making an angle equal to angle of friction
IF THE MINIMUM HORIZONTAL FORCE REQUIRED TO DRAG A HEAVY BODY ON A ROUGH HORIZONTAL SURFACE BE n TIMES ITS MAGNITUDE,WHEN IT BE INCLINED TO THE HORIZONTAL AT THE ANGLE OF FRICTION .FIND THE CO-EFFICIENT OF FRICTION.
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16 Answers
1n TIMES ITS MAGNITUDE??? wat magnitude are u tlking of??write the question properly vardaaN!
231yaar AISA LAGTA HAI KI LEARNING.... NE PCM KI ABC NIKAL DI HAI
HEY LERNING.... FIRST SEE THE QUESTION COMPLETELY,UNDERSTAND IT AND THEN GIVE UR NOSTALGIC VIEWS OK..LOL
1chalo let me teach u punctutation marks starting with COMMA....
1.typically it refers to a momentary pause!
2.in physics...whenever u describe a physical entity realted to other entitites [which are word forms of the equations ]....commas r not to be employed!
1ARRE TU TOH NARAZ HO GAYA AALE AALE HUCHI KU ..LOL
DEKH YAAR TU MERE BADE BBHAI JAISA HAI,NARAZ MUT HO.
OK I WILL TAKE CARE NEXT TIME OK.
1ruk be isko padh from WIKIPAEDIA::::::::::
The comma ( , ) is a punctuation mark. It has the same shape as an apostrophe or single closing quotation mark in many typefaces, but it differs from them in being placed on the baseline of the text. Some typefaces render it as a small line, slightly curved or straight, or with the appearance of a small filled-in number 9.
The comma is used in many contexts and languages, principally for separating things. According to the Oxford English Dictionary, the word comma comes directly from the Greek komma (κόμμα), which means something cut off or a short clause.
agey se apni hoshiyaari marne se pehle question likhna sikho!
1THANK U YAAR,PAR THE QUESTION IS NOT SOLVED YET MY BROTHER.
THANKS FOR GIVING INFO ABOUT COMMA.DEKH YAAR GUSSA MAT KAR,TU MERE BADE BHAI JAISA HAI.I RESPECT U A LOT............................
1ok coming back to question i interpret it as this
IF THE MINIMUM HORIZONTAL FORCE REQUIRED TO DRAG A HEAVY BODY ON A ROUGH HORIZONTAL SURFACE BE n TIMES ITS MAGNITUDE WHEN IT BE INCLINED TO THE HORIZONTAL AT THE ANGLE OF FRICTION .FIND THE CO-EFFICIENT OF FRICTION.[no comma there for me :P]
i m getting answer as : coefficient of friction=√[4n2-1]
1DEKH YAAR TUNE KHAMAKA KI BEHES SHURU KAR DI HAI,(COMMA) BUT THE QUESTION IS NOT SOLVED.DEKH YAAR:
1) THE RIGHT WAY COULD BE THAT FIRST U HAD SOLVED IT AND THEN GAVE UR NECESSARY ADVICE.
2)IT IS THE INDISPENSABLE DUTY OF UR TO UNDERSTAND IT FIRST.
3)AS U CAN SEE QWERTY HAS ALSO UNDERSTOOD THAT VERY WELL,PAR BHAIYA AAPSE KAHA GALTI HO GAYI I DONT KNOW.
U HAVE A HABIT OF ELONGATING UNECESSARY THINGS.I KNOW U R VERY GOOD BY HEART,BUT PLSS MAINTAIN IT BY UR WORDS ALSO.................
1ok repying to ur points one by one:
1.for solving problem firstly need to be corrected first[read my post no.11 i first wrote corrected problem :)]
2.to understand problem need to be written correctly[comma is changing the whole meaning of the problem!]
3.not only qwerty but i also did get it coz it was but obvious tht comma need not be there but as a CANDIDATE OF EXAM...u must not assuming any thing as obvious.... u should either leave a doubtful question or ask for right one!
1ok fine but u have not got correct ans pls see post no 8.
AND ONE THING IF I HURT U I M SORRY BCOZ SEE UR SECOND POST U HAD MADE USE OF NON ELLIGIBLE WORDS WHICH MADE ME ANGRY AND U ALSO KNOW WHO HAD STARTED FIRST.SEE U R AGOOD GUY AND WE ALL R HERE FOR ONLY ONE MISSION THAT IS IIT OK.
ALSO I DONT MIND IF U GIVE ME ADVICES AS U R MY ELDER BROTHER BUT PLSS MAINTAIN THAT ATTITUDE MAN.U R NOT LIKE THIS I KNOW FROMI NSIDE U R VERY SOFT.
AGAIN DONT MIND AND IF U HAVE ANY STRANGE THINGS, U CAN MAIL ME AT
vardaank786@yahoo.com
SEE ONE THING I LIKE ABOUT PRITISH IS THAT HE IS GOOD BY HEART AND NEVER IGNORE TO POST ANS OR INFORMATION.
SORRY BUT WE R DIVERTED FROM TOPIC,BUT U STARTED FIRST........
106
here k = coeff of friction
@ = θ (in diag = angle of friction)
F = force when inclined at angle of friction
F(hori) = Horizontal force
1LOL!!!!!!!!was this tht the question meant???
u know wat i interpreted it as???
i solved it for a inclined plane case LOL!!!!!!!!!