variable mass system

can anyone explain me how to solve problems involving variable mass systems.. except rocket propulsion... please..?

35 Answers

21
tapanmast Vora ·

iska PERFECT FINAL ANSWER KYA HAI?

106
Asish Mahapatra ·

nishant bhaiyya:
can u solve that question so that atleast i can get some hint how to do them... i cant get head or tail of this one...

21
tapanmast Vora ·

here : F = d(mv)/dt= m(dv/dt) + v(dm/dt)

m will be minst. rite, ie (M - μt + m) and dV/dt = a; dM/dt = μ

thn i guess we'll hav to integrate frm ini. vel V to final inst vel 0

1
Kumar Satyajeet ·

hi.....asish....

Q) Acart moves in horizontal dirn due to a cost. focre F in same dirn. In the process sand spills thru a hole in the bottom with a const. vel m kg/sec. Find accn and vel of the cart at any time instant t.(initial mass of cart+sand=M and vel = 0)

1
skygirl ·

waise i will give a simple problem.

A trolley has a small hole on one side, from which sand falls in the forward direction at a rate of μ kg/ hr at a velocity of v relative to the trolley!

total mass of the sand on trolley is M
mass of trolley is m

initial velocity is V

find the time after which it stops.

doubt it ever stop ?

for that we will get a term ln0 .. which is undefined..

1
skygirl ·

net force on the trolley = mdv/dt = -v μ/(3600)

=> V∫V'dv/v = -μ0∫tdt/(3600m)

=> ln(V/V') = μt/(3600m)

to find out t when V' =0 is impossible.

we can find out t for some particular value of V.

106
Asish Mahapatra ·

@kumar.. i was doing irodov yesterday and saw that prob... but i cudnt solve it.. anyone mind helping out??

1
skygirl ·

bhaiya pls anser post #23.

1
skygirl ·

#22.)

let at time t, mass of the trolley = m = [mo-μt]

and its velocity be v.

afetr time Δt, mass =m-Δm [Δm=μΔt]

v ---> v+Δv

by momentum conservation:

(m-Δm)(v+Δv) + Δm(v-u) = mv [u=velocity of the sand wrt trolley]

=> (m-Δm)Δv = Δm.u

=> Δv = Δm.u/(m-Δm) = μΔt.u/(m-μΔt)

=> Δv/Δt = μ.u/m-μΔt

[since Δm --->0 as delt-->0]

so, dv/dt = μu/m = μu/(mo-μt)

=> 0∫vdv = 0∫tμu/(mo-μt) dt.

=> v = u ln[mo/(mo-μt)]

now u =Ft/m. = F/(m/t) = F/μ = velocity of sand wrt trolley.

put this value in place of u..........

62
Lokesh Verma ·

instantaneously :)

1
skygirl ·

v = F/μ ln[mo/(mo-μt)]

21
tapanmast Vora ·

HMMMMM........ wonderful proof!!! [50]

1
skygirl ·

arey yeh same hai .. just like rocket ...

21
tapanmast Vora ·

haan!!!

par mene socha ki Pink wink kuch nahi hai to shayad rong hoga isliye dekha hi nahi tha, abhi DEKHA

[78]

1
skygirl ·

[3]

woh... bhaiya sat-sunday very busy...

isiliye i wont disturb him by doing jhagra for pink [3]

62
Lokesh Verma ·

it will never stop sky :)

1
skygirl ·

k.. :)

24
eureka123 ·

I believed this one was in syllabus...but today again 3 people told me this topic is not in syllabus.....

what do tiitians say ??

62
Lokesh Verma ·

ye typing error tha... solved got replaced by loved (:)

nothing like that in my mind :P

waise i will give a simple problem.

A trolley has a small hole on one side, from which sand falls in the forward direction at a rate of μ kg/ hr at a velocity of v relative to the trolley!

total mass of the sand on trolley is M
mass of trolley is m

initial velocity is V

find the time after which it stops.

24
eureka123 ·

2)Impulse method
Δp=J
=>pf-pi=F.t
(here both initial and final momentum will contain variable mass term.....)

Write correct initial and final momentum taking rocket +fuel as system or any other thing like truck with sand......[1][1]

106
Asish Mahapatra ·

eureka can u explain using sum example...

suppose.. there is a heap of rope on a table...of mass M and length L .... what will be the valocity of te rope when the rope has slid down by a dist x??

24
eureka123 ·

that can be done using energy method......it wont require all this.......

btw i have to go now,,,,wil reply later

11
Mani Pal Singh ·

@asish
THIS IS NOT IN SYLLABUS
SO I RECOMMEND NOT TO WASTE TIME ON IT

24
eureka123 ·

It is very much in the syllabus.......[1][1]

106
Asish Mahapatra ·

yes eureka.. sry for such a late reply..kyonki net ka wire kho gayaa tha

can u solve the question i had given.. and how it wud have been different. if the chain was not heaped but was laid on the table on a single line.... wud it have been different?

62
Lokesh Verma ·

Variable mass is solved by momentum conservation in a small time...

If there is an external force you just have to consider that too..

In theory it is very simple. .but a lot of people and sometimes the books themselves will make you believe that it is very difficult!

The most basic thing to do is F=d(mv)/dt

106
Asish Mahapatra ·

Variable mass is loved by momentum conservation in a small time... [7]

abd bhaiyya can u plz div me some problems so that i can try...

24
eureka123 ·

One is which involves log (common method) and other one does not involve log but will involve correct selection of system

1)Instantaneous mass=Force other than impulses + Thrust due to impulses
=>m.dv/dt=Fext+vrelativedm/dt

24
eureka123 ·

sir....i also wrote the same..[1]

24
eureka123 ·

@ asish should i do this question for u.. or do u want to try???????[7]

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