1v is w X r w is angular velocity r is radius vector
in given q
w=i-2j+2k
r is -(2i-j-k)+(2i+3j-4k)=4j-3k
so v=w X r = -2i +3j +4k
hence [01]
If a rigid body is rotating about an axis passing through the point 2i -j - k and parallel to i-2j+2k with an angular velocity = 3 rad/sec , then find velocity of the point whose position vector is 2i + 3j - 4k :
[01] -2i+ 3j + 4k
[02] 2 i-3j + 4k
[03] -2i + 3j - 4k
[04] -2i - 3j - 4k
HOW TO SOLVE THESE TYPE OF QUESTIONS ?
Answer : [ 01 ]
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