as from the figure.. guess its pi/2
A ring of radius R rolls on horz. ground with linear speed v and angular speed omega.For what value of theta the velociy of pt. P is in vertical direction (v<omega(R))
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5 Answers
Lokesh Verma
·2008-12-23 10:06:18
For the horizontal velocity to be zero,
V-ωRcosθ=0
so cosθ=V/ωR
Hence θ=cos-1(V/ωR)
Lokesh Verma
·2008-12-23 10:06:49
@Unique.. that is the case when V=0...
try to see that from the formula that i derived above...!!