DO xplain in detail.
as in (i)on d surface of earth
(ii)r<R
(iii)r>R
62see the basic is that it will be
if mass enclosed in the radius r= M
then the field will be GM/r2
so the quesiton is to find M
when R=r or r>R then mass enclosed is the whole mass of the earth... = Me
when it is less, it is the Mass times the ratio of the volume.
so it is Me(r/R)3
1see u can do it it with law of gravitational flux . like total electric flux through a closed surface is q/ε similarly the gravitational flux through a surface is 4π Gm. try it it works....
The logic...........similarity of gravitational and coulomb's forces
