1try to learn hindi da. really helps . ;)
JEE ke saath saath hindi bhi padna hai
alongwith JEE you've gotto study hindi also
39in general we have if v1 is the velocity of incident wave and v2 is the velocity of the transmitted wave,and A is the amplitude of the incident wave, then
the amplitude of the transmitted wave is given by
At=(2v2/v1+v2)A
its a general formula and can be used anywhere.
21hey mathe matician can u pl xplain da foll.
(2v2/v1+v2)A =2/3A.
is it a generalised formula or sumthing........
othtrwise gr8 soln... thnx .....
39let v1 be the velocity in string 1 and v2 be the velocity in string 2. as tensions r same, then v is inversely proportional to √μ. we get v1=2v2.
now let A be the amplitude of the iincident wave, then the amplitude of the transmitted wave is given by (2v2/v1+v2)A =2/3A.
as energy is directly proportional to A2 and other parameters are constant, we get fraction of incident energy is 4/9.
21oh this post keeps getting bigger by my posts only ..... [2] [2]
Is ther no one here to solv this un??????? [7] [7] [7] [7]
21THE SAME FORMULA U TOLD.......
BUT NOT GETTIN 4/9.........
@SANKARA : OH K I'LL WRITE KUM HINDI LOL.... [1]
3i cant understand hindi da.
please post ur replies in English
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1waise bhi hoga kya:O meine woh soocha ni .......
yeh boards jaan le re hai :(
3can u give hint integrations.
how much of the wave will get reflected and how much of the wave will get transmitted
1dunno...........nt feelin like doin.......
i guess wnt get d results .....
sorry sorry sorry sorry....
1power=enrgy/time=2(pi)^2*μ*v*f^2
f=frequncy
isse aana chahiye
sorry if dats wrng
aaj kal boards karke dimag mein junk ho gya hai
