Wedge Constant?

Anyone can please tell what is it and where and how to use it?

13 Answers

1
rony027 ·

constant or constraint??????

71
Vivek @ Born this Way ·

Anyways .. got it! May be it is related to this sum..

The wedge angle is 37°

23
qwerty ·

wat are the masses ?

3
msp ·

The constraint which i think is the acceleration of the wedge is only on the x axis,and we need to know the masses

71
Vivek @ Born this Way ·

Nothing given.... .

That's why I'm confused..

11
Khyati ·

Oye Vivek I aksed many of my friends regarding this, searched about it in google, books, there is nothing about it in wiki also. So I posted it in physicsforum, even there also I didnt got any info about it. Now they are asking me from where I got to know about this [3]

http://www.physicsforums.com/showthread.php?s=f86c5197093c053fa0b8e780750993e4&p=2935868#post2935868

I think its Wedge constraint and not wedge constant [1]

11
Khyati ·

Take the massses as ma and MB [1]

Yeh question kahan se mila tumhe, Vivek

6
AKHIL ·

ya
it wud be wedge constraint only...

11
Khyati ·

nah its wedge constant only, its use for some kinds of sum solving related to wedge

will give more info regarding this as I'll get [1]

3
msp ·

it may be in an engineering mech book,ok for jee it may be nice to leave this one.

11
jeetopper jee ·

A concept used in such questions is the common normal concept which you guys are calling wedge constraint.

IT SAYS THAT FOR ANY TWO BODIES TO REMAIN IN CONTACT THEIR RELATIVE VELOCITY ALONG THE COMMON CONTACT SURFACE SHOULD BE ZERO.

THAT WAY if we assume wedge to be moving in the x direction with acceleration a then by the method i ve elucidated

15(cos37°-sin37°)=acos37°
solving yo get a.

THERE ARE SEVERAL OTHER WAY OF APPROACHING A CONSTRAINT RELATION>

ANOTHER Very USEFUL METHOD IS RELATIVE VELOCITY >IN FACT THIS CONCEPT OF RELATIVE VELOCITY ACCORDING TO ME IS A VERY POWERFUL TOOL IN SOLVING INTRICATE QUESTIONS IN MECHANICS(ALTHOUGH NOT THE ABSOLUTE ONE................:D)

COMING BACK TO THE POINT try to solve this by SITTING ON THE BIGGER BLOCK AND WATCHING THE OTHER BLOCK .

See ya later...

11
Khyati ·

Thanks Jee 2012 Air 1 [3]

for this info [1]

71
Vivek @ Born this Way ·


COMING BACK TO THE POINT try to solve this by SITTING ON THE BIGGER BLOCK AND WATCHING THE OTHER BLOCK .

Tried this... Such sums were solved by me... But couldn't do this one.

15(cos37°-sin37°)=acos37°
solving yo get a.

I had exactly the same solution but couldn't understand this.... Now getting a bit.!

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