What is the velocity of flow of liquid??

bhai BERNOULLI T try ki kya ???

K... mani i knw just i gav dis Q 4 others..(X! studs) (My own question-low standard!!-haha i know it is easier), but some will feel difficult lukin at the different parameters...

ya not that difficult......................

should we solve or is it OK????

Applying Bernoulli,
P + ρg(h-x) + ρv1²/2 = P + ρv2²/2
==> v2²-v1² = 2g(h-x) ... (i)

Ï€r²v1 = Ï€r'²v2 .. (ii)

==> v1 = (r'/r)²v2

Putting,
v2²(1-(r'/r)⁴) = 2g(h-x)

as hole is small r'/r ≈ 0

so, v2² = 2g(h-x)

so v2 = √2g(h-x)