11I am in desperate need of help, guys... [17]
so please give full explanation and bear with stupid doubts which i will ask
A 10 cm column of air is trapped by a 8 cm column of Hg in a capillary tube.....the tube is horizontallly fixed as shown in the figure at 1 atm pressure. Calculate the length of air column when the tube is fixed:
(a) vertically with open end up
(b) vertically with open end down
(c) at 45° from horizontal with the open end up
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UP 0 DOWN 0 0 7
7 Answers
11
39similarly when end is down. the pressure is 76-8 =68. and same method as above
1357Just try PV=constant for the gas trapped
as when it is up
P=P0+hÏg
1357for a)
initially pressure of trapped gas = 1 atm=76 cm of mercury
final pressure is P0+hÏg=76 cm + 8 cm of mercury=84 cm
P1V1=P2V2
76*A*10=84*A*l
l=760/84=190/21
39for c is pressure is 76- 8 cos 45 and same method as above.
the main point is t use boyle`s law.