Mechanics - WPE2

1

ANKIT MAHATO ·2009-05-08 04:01:54

:D .. this problem can be solved dude !!

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ANKIT MAHATO ·2009-05-08 04:03:03

final ht. in both the vessels is (h1 + h2)/2

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ANKIT MAHATO ·2009-05-08 04:03:31

now use energy method ....

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ANKIT MAHATO ·2009-05-08 04:03:47

wait i am posting the entire soln.

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ANKIT MAHATO ·2009-05-08 04:12:24

initial energy of the system = (ÏAh1)*g*(h1/2) + (ÏAh2)*g*(h2/2)
final energy of the system = 2*(ÏA(h1 + h2)/2)*g*((h1 + h2)/4)
W done by gravity = (ÏA)*g*((h1²/2) + (h2²/2)) - (ÏA)*g*((h1² + h2² + 2h1h2)/4)

(1/4 )*(ÏA)*g*(h1 - h2)²

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ANKIT MAHATO ·2009-05-08 05:05:20

abey isse toh check kar le sahi hai ya nahi !

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1

JOHNCENA IS BACK ·2009-05-08 05:11:04

sahi hai yaar!

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JOHNCENA IS BACK ·2009-05-08 06:05:52

BUT HERE WORK DONE SHUD BE ZERO NA......SINCE K_f - K_i=0

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9

Celestine preetham ·2009-05-08 06:30:13

WD by external source = change in mechanicalEnergy

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