Using an approximation:
log(3.9*10^15)≈log(4*10^15)
=2log2 + 15
=2*.301+15
=15.6
I got this step from a FIITJEE solution.....
antilog(15.593)=3.9*1015
how to do that???? (no data was not given in the question!)
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3 Answers
Ketan Chandak
·2012-01-27 19:01:38
dey assumed u alrdy knw de value of log 3....
although de answer is not completely correct....
coz log(3.9*1015)=log 33+log1015
which is 3 log 3+15 log 10=16.431
Swaraj Dalmia
·2012-01-28 03:20:32