106Total Students Appeared: 177
Average Marks: 2.43
Maximum Marks: 10.00
Your Marks: 9.99
Your Percentile Rank: 53.11
Bhaiyya, my answer is correct....so how can it be percentile 53.11 and 9.99/10?
You can put down all your complaints.. errors on tests and anything that u dont like about this site.. on this thread.
I will try to make it sticky so that it is always in the home page view!
Or may be link this thread to analyse tests!
Feel free to bash us and kick us or do something worse...
We never mind constructive criticism :)
We will try our best to serve ur purpose.. no matter what :)
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308 Answers
106
33In home page when i am typing in search box at top right corner...
instant chat refreshes and cursor positions to instant chat... so some text i type in that... have to again click at search box... when instant chat refreshes it is necessary to position cursor there...
3yep same thing wat happened to ashish happened to me..........................
otherwise this site is marvellous!!!!![1]
62I will check that
isnt Mr Analyst working..
we upgraded our tests recently... i guess this is a side effect of that..
Will check it guys :)
1ok now this sounds strange but my perccentile bars r not appearing in chrome but they r in firefox [7][7]
1but it happened only today i always use chrome for targetiit but there was no prob
1strange i just cheaked now the bars r shown thanx niways bro
1ok sry forget my above post bars r still not appearing on chrome (prob occured only today)
i cheaked again at fox not chrome and wrote that foolish post sry fr that
11Total Students Appeared:403
Average Marks:3.34
Maximum Marks:40.00
Your Marks:25
Your Percentile Rank:36.8
WHY 36.8%
3#46 PAGE 2 amit91!!!!u suck not the site ... havnt u heard of ctrl + C and ctrl +V ????????
[9][9][9][9][9][9][9][9]....
AT LEAST APPRETIATE WAT THEY HAV DONE
33:(
:(
my name is not shown in instant chat... nor in my home page.. where Welcome ........ is written..
:(
:(
1bhaiyya can u add more smilies like in yahoo messenger.....[1][1][1][1][1].........
11T51
Q10 lim(x→∞) (x+1)(x2+x+2)
a) 0
b) 1
c) ∞
d) does not exist
Q5 lim(n→∞) (Σi3)/n3 (where summation is from 1 to n)
a) 1
b) 1/2
c) 1/3
d) 1/6
the ans are bolded
do u agree??????????
621) yes i gree
2) it is not correct i think! it should be zeroo
The question should have been i2
1bhaiyya can u include more smiies in targetiit.com at yahoo messenger........
1Q5 The standard reduction potential of Li+/Li, Ba2+/Ba, Na+/Na & Mg2+/Mg are -3.03, -.73, -2.71 and -2.37 volt respectively. Which one is the strongest oxidizing agent?
a) Na+
b) Li+
c) Ba2+
d) Mg2+
Your Answer: (c)
Correct Answer: (d)
Score: -1
Explaination :
since the reduction potential is maximum for Mg2+, it is strongest oxidizing agent.
1plz make a notification system that we get notified by emails whenever sm1 answers our Q or after we have reviewed a Q so that we can know that we have been answered or if sm1 has given ans later than us(2nd case) and the ans was better than us.........
it'll be too helpful, since there may b that ny1 forgets to review his Q as such, but the mail will help him or even, he can get notified of a better ans
11iss mein koi conceptual mistake hai
to please help
T38
Q6 find dy/dx where y=secxtanx
a) secx(1+2tan2x)
b) secx(1+tan2x)
c) secx(sec2x+2tan2x)
d) none
Your Answer: (d)
Correct Answer: (a)
Score: -1
Explaination :
u=secx v=tanx dy/dx=d(u.v)/dx=u(dv/dx)+v(du/dx)
KAISE[17]
106dy/dx where y=uv and u,v, are both functions of x is given by ...dy/dx = d(u.v)/dx=u(dv/dx)+v(du/dx)
here. u=secx, v=tanx
so, dy/dx = secx.d(tanx)/dx + tanx.d(secx)/dx
= secx.sec2x + tanx.secx.tanx
= secx(sec2x + tan2x)
= secx(1+2tan2x)
i think 2tan2x is just a typo..
1bhaiyya can u display the messages posted by different friends displayed as in orkut........
1bhaiya ,can we have sections of assertion reason,mcq etc so that one can have a quick rev of solved questions