1yah
hey lets start a thread for the prep of bitsat....will be posting in questions that might be of some relevence to the exam...
guys...plz post in ur questions
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127 Answers
1and one more
the integral part of (8 +3√7)n is
an odd integer
an even integer
zero
nothing can be said
23@ guruji, is it 1,3 butadiene ?? more stable the alkene, less is its heat of hydrogenation .....
11#33
ans is odd integer...
Let (8 + 3√7)n = I + f
and let f ' = (8 - 3√7)n .....(0 < f ' < 1)
now I + f + f' = (8 + 3√7)n + (8 - 3√7)n
= 2(C0 8n + C2 8n-2 (3√7)2 + .....)
= an even integer...
so f + f' = an integer....
now 0 < f < 1 (as f is the fractional part)
and 0 < f'< 1 (shown above..)
adding... 0 < f+ f' < 2
since 1 is the only integer between 0 and 2
f + f' = 1
now I + f +f' = an even integer
==> I + 1 = an even integer
==>I = an odd integer...
11# 15 no. 4 (though just a guess....)
is the answer (mn)m - 1
???
1yeah it will be 1,3-butadiene as more stable the alkene less is the heat of hydrogenation..
And more alkylated the alkene is more it is stable...
11#29 ans is d
cos x = tan x
==> cos 2 x = sin x
==> 1 - sin 2 x = sin x
==> sin 2 x + sin x - 1 = 0
==> sin x = -1 ± √1+42 = √5 - 12 = 2 √5 - 14 = 2 sin 18
11also another qsn in #35....does it always holds true...i mean to say in such problems does the answer always come out to be odd integer???
1@ guruji...i did nt noe the ans to ur ques...but now i do...thanks...plz keep on posting such questions
1when an electron is emitted from a nucleus, then what is the effect on its neutron proton ratio?
39An electron going away from the nucleus is equivalent to the addition of a proton to the nucleus(as is in the case of beta decay, the atomic number increases). So the neutron proton ratio decreases(as protons increase).
1of course it is, coz we talking about the sections, which are always different...
1Didi, check question 2, #15
I guess its incorrect.
It should be:- If the roots of equation (x-b)(x-c) + (x-c)(x-a) + (x-a)(x-b) = 0
1If it is so, answer is B)
a+b\omega +c\omega ^{2}
Just expand and rearrange the expression. Put \Delta =0
1@ ray, ur ans correct...
jus give me the explaination of that permutains one
1It was just simple counting and grouping.
Let me see how can I explain.
Not very good at explaining..
1Permutation-
For 1st section, we have mCn choices, for 2nd, we have m-nCn choices, for 3rd we have m-2nCn choices...and so on till nCn.
Hence the total ways.
1no sandipan, the answer is not always ood.. Take for example find the integral part of (4+2√5)2n+1, where the answer turns out to be even......
1Quadratic-
the given equation can be written as-
3x^{2}-2\left(a+b+c \right)x+ \left(ab+bc+ca \right)=0
For equal roots
\Delta =0
\Rightarrowa^{2}+b^{2}+c^{2}-ab-bc-ca=0
(a+b\omega +c\omega ^{2})(a+b\omega ^{2}+c\omega )=0
1value of
\int_{0}^{sin^2\phi }{sin^{-1}\sqrt{\phi }}d\phi + \int_{0}^{cos^2\phi }{cos^{-1}\sqrt{\phi }}d\phi
k i get the derivative of this funtion as 0 using leibnitz, but then hw to find the value of the funtin??????
1@ pritish...y are we considering the beta decay,?????
can this nt be the case of simple ionization....and therefore the ratio should remain constant?>>?>?
39cat, its your own question..it's talking about electron emission, not electron donation or electron sharing.