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Is there any website where we can ask doubts for JEE and they answer soon for free or for money less than 100 rs??

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a1b2c3 shivam jain ·Mar 21 '12 at 9:00

evaluate limit x tends to '0' (sin(pi(cos square x)/x square

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johncenaiit ·Mar 21 '12 at 21:53

@ Athenes .... i know many websites... but target iit is best (for jee)

@a1b2c3,
$lim x \to 0 x 2 s i n (π c o s 2 x) = lim x \to 0 x 2 s i n (π - π c o s 2 x) = lim x \to 0 x 2 s i n (π s i n 2 x) \times π s i n 2 x π s i n 2 x $

Ans : $π$

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Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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