Is there any website where we can ask doubts for JEE and they answer soon for free or for money less than 100 rs??
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2 Answers
johncenaiit
·Mar 21 '12 at 21:53
@ Athenes .... i know many websites... but target iit is best (for jee)
@a1b2c3,
limx→0x2sin(πcos2x)=limx→0x2sin(π−πcos2x)=limx→0x2sin(πsin2x)×πsin2xπsin2x
Ans : π