Miscellaneous - ENERGY OF AN ELECTRON..!!!!

106

Asish Mahapatra ·2009-04-04 05:13:38

-13.6*1/n² = -3.4 eV
==> n = 2

So, angular momentum = nh/2Î = 2h/2Î = h/Î

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11

Subash ·2009-04-04 05:13:56

h/Ï€

because -3.4 corresponds to n=2

L=nh/2Ï€

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1

Pavithra Ramamoorthy ·2009-04-04 05:19:29

units pls????????

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Aditya ·2009-04-04 05:20:55

J-sec

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Pavithra Ramamoorthy ·2009-04-04 05:23:26

can u pls express d final value in kgm²x^-1

?????

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106

Asish Mahapatra ·2009-04-04 05:26:16

6.626*10^-34/3.14 â‰ˆ 2.1*10^-34 kgm²x^-1

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Pavithra Ramamoorthy ·2009-04-04 05:29:01

no dude....... in d ans it has been given as 10^-30........

dats d prob...

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106

Asish Mahapatra ·2009-04-04 05:30:16

then its probably wrong

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Pavithra Ramamoorthy ·2009-04-04 05:31:28

hey.. all d 4 options they ve given d same powers... but only diff values

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1

Aditya ·2009-04-04 05:38:54

Then probably it should be 10^-32J s from ang. mom. = mvr....by d way i always had a doubt when to use mvr n when 2 use nh/2Ï€

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Pavithra Ramamoorthy ·2009-04-04 05:43:37

k.. if we use mvr wat is r??????????

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Aditya ·2009-04-04 05:56:49

r is 0.53*n² here...!

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