Phenol underset{ ext{(ii) }C{{O}_{2}}/{{140}^{o}}C}{mathop{xrightarrow{,, ext{(i) NaOH},,}}},Axrightarrow{{{ ext{H}}^{+}}/{{H}_{2}}O}Bxrightarrow{ ext{A}{{ ext{C}}_{ ext{2}}}O}C. In this reaction, the end product C is a) Salicylaldehyde b) Salicylic acid c) Phenyl acetate d) Aspirin
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