A = Pb
B = Chloroplumbous acid = H2PbCl6
C = T.E.L.
An element A belongs to 14th group and occupies period no 6. A reacts with conc.HCl to give B an acid. A is used to prepare C which is used as an antiknock in automobiles . Identify element A and compound B &C.......
MENTION THE REACTIONS.........
A VERY SMALL BUT BIG CORRECTION DUDE..............
B= CHLOROPLUMBIC ACID..........................(H2PbCl4)
as already answered of a and b, i wud ans the combined of a,b and c
a) lead(Pb)
b) chloroplumbus acid(H2PbCl2)
c) lead chloride(PbCl4)
tapan got two rit........
the ans is
A = Pb
B = Chloroplumbic acid = H2PbCl4
C = T.E.L.(tetraethyl lead)
everyone please don't keep any doubt in ur mind regarding question 2 :
Concentrated HCl evolves hydrogen and also forms Chloroplumbic acid
Pb + 2HCl → PbCl2 + H2 ↑
PbCl2 + 2HCl -> H2PbCl4 (chloroplumbic acid)