Are you sure about the question?
Let the numbers be \mathbf{2+a_{1}d , 2+a_{2}d , 2+a_{3}d , 2+a_{4}d } \textbf{ and } \mathbf{2+a_{5}d}
Let \mathbf{S=a_{1}+a_{2}+a_{3}+a_{4}+a_{5}}
Therefore,
\mathbf{10+4S=100,\rightarrow S=22.5}
which is not possible since S is an integer.