for the 1st ques of PART 1
Sin50°-sin70°=2cos120°sin10°
=-sin10°
sin10°-sin10°=0
Part 1
1. sin 50 - sin 70 + sin 10 = ??
2. 5 cosθ + 3 cos(θ + Π/ 3 ) + 3 lies in the interval.................
3.The circle 1 bisects the circumference of the circle 2...for wat value of K??
c1 : x^2 + y^2 -6x -4y +k=0
c2 : x^2 + y^2 -8x -6y +23 =0
4. There are three vectors forming adjacent sides of tetrahedran what is the angle of one of the sides making with the base of the tetrahedron(ie the triangular side)??
Part 2
1) Cpd 1 is more stable than cpd2 , coz l.p. of electrons on O....Am i rite??
2)The Incorrect order of acidity is given...(bit confused on language)....Is the given sequence correct(especially CH4 and NH3)
3)My ans: O-methyltoluene is more basic than aniline(elec donating gruop...... but d ans given is opp...why??
4) IUPAC name??
5)It shows keto enol tautomerism....rite(But ans given is not....why??)
If -CH2 -COOH is attached to benzoic acid at para position , then what is the IUPAC name??
lets begin with part 2
1) NO ur answer is wrong
3° R+ is more stable as compared to the 2°R+
2) the order given is correct
As the electronegative character ;the acidic character increases(refer to textbook)
3) remember that NH2 is deactivating and is meta directing
4) pent-2-en- 2,3-diol
5) bhai benzene hai saath mein
resonance ho jaaegi and it will hinder the keto enol tautomerism
yes......RIP...but the lone pair will involve in conjugation rite??
3)..me too got d same ans but in fiitjee package it was given 2-methyl but-2-ene-2,3-diol....Reason...The functional grup shd b given least number(OH attached at carbon 1)
Sri draw the structure given by the answer
according to the given answer the ques would have been like
for the 1st ques of PART 1
Sin50°-sin70°=2cos120°sin10°
=-sin10°
sin10°-sin10°=0
It means that the common chord is a diameter of the second circle
try figure
find the common chord by subtracing the two equations
and this line passes through the centre of the second circle ie(4,3)
from there get k