@KRI... d events aren't related to d bags... it's related to d experiment...
well, i solved it for white n red and u solved it for black n red... so obviously our answers dun match...!!!
@KRI... d events aren't related to d bags... it's related to d experiment...
well, i solved it for white n red and u solved it for black n red... so obviously our answers dun match...!!!
what and why's is this rank and others all about...
i did R1+R3
R1-4/3(R2)
AND THEN SIMPLIFICATION.......THIS SIMPLE TRICK APPLIES FOR ALL
[33]
What am I expecting???
Simple answer: Expecting an early Diwali
Got set 3, got the probability question (6 marks) completely wrong!!
[94]
i got set 2...
wat is d correct answer to the probability(6 marks) question?
@maddybaddie... y dun u post d question in d forum... evry1 will have a luk at it... :)
sure...
Coloured balls are distributed in three bags :
Colour of Ball
Black White Red
Bag I : 2 1 3
Bag II : 4 2 1
Bag III : 5 4 3
A bag is selected at random and then two balls are randomly drawn from the selected bag. They happen to be white and red. What is the probability that they came from bag II ?
sum1 pls post the solution...
i'm getting d answer as 110/397 ...
see if my method is correct...!!!
A - Event dat d balls are drawn from bag II
B - Event dat d drawn balls are red n white...
P(A/B) = P(A∩B) / P(B)
= (1/3 x 2/7 x 1/6) / [1/3 {(1/6 x 3/5) + (2/7 x 1/6) + (4/12 x 3/11)}] = 110/397
wrong...!!! see post #48...
my ans is wrong!!!!!!! :( :( :(....
ur method is correct i think......i did it d same way but made a silly error sumwhere :( :( :(
@:-)
there are 3 events ::
E1: BAG 1 IS SELECTED
E2: BAG 2 IS SELECTED
E3: BAG 3 IS SELECTED
A: DRAWING 1 RED AND 1 WHITE.
hmm.......i forgot to write that integration question of six marks........[2][2][2]..[17][17][17]........and got a small mistake while calculating the matrix question.....
yeah, i've used Bayes theorem... well, procedure is correct but i'm missing sth...
whats dat...!? i dunno...!!!
yeah got it... thanx... :) ........ n sorry...
dis is d expression...
P(A/B) = (2C1x1C1/7C2) / [(1C1x3C1/6C2) + (2C1x1C1/7C2) + (4C1x3C1/12C2)] = 110/551
[1]
did paper twice....becoz finished in 1.5 hrs......[3][3]....but still made a silly mistake.......[2][2].got the scolding..[2][2]
me too ,did it 1.5 hrs,checked all questions again but one(and that one is where i made a mistake) [2][2][2][2][2]
0 ?? What if first row is correct and the formula( A= IA and I =A-1 A)- I think it carries 2 marks please reply...
very very easy
par meine ek 6 mark ka galat kar ke aagaya
paper was quite short i got set 2
made a stupid mistake 3 + 7 + (1 X0) = 11
otherwise ok got rest of the ans
@sriraghav
3 -2 8
-4 3 -12
3 -2 9
Adj A =
3 -4 3
-2 3 -2
8 -12 9
det A = 3*3 - 8
= 1
A-1 = Adj A / det A =
3 -4 3
-2 3 -2
8 -12 9