1half life is 10 s therefore λ=0.63/10 and hence mean life is 1/λ
At a given instant there are 25% undecayed radioactive nuclei in a sample. After 10 seconds the number of undecayed nuclei redu ces to 12.5%.
Calculate:
(i) mean life of the nuclei
(ii) the time in which the number of undecayed nuclei will further reduce to 6.25% of the reduced number.
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7 Answers
1
106half life = 10 sec = 0.693/k
So, mean life = 1/k = 10/0.693 = 14.43 sec-1
if i dont understand the language (see how poor my english is ) part 2 is 40 sec ??
39its `of` the reduced number,
sorry nowadays trying to learn fast typing :P
and asish , first part u have given the right answer
62@Bhargav.. it is called "learn typing" :P not "learn fast typing" :D :P
