radioactivity

10 gms of 57Co kept in an open container beta-decays with a half life of 270 days. The wt. of the material inside the container after 540 days will be very nearly

(A) 10 g

(B) 5 g

(C) 2.5 g

(D) 1.25 g

7 Answers

1
Ricky ·

Since " T 1 / 2 " = 270 days , and given time = 540 days = T1 / 22

So , the required amount of Co = 14 . 10 gms = 2 . 5 gms

1
seoni ·

10?

cos' M rxtnt~M product

1
Ricky ·

If you are asking about the total weight of the inside the container after 540 days , then it would be 10 gms due to mass conservation . If you are asking the remaining weight of Co , then the answer is 2 . 5 gms .

49
Subhomoy Bakshi ·

yup..it shud be 10!!!!

6
AKHIL ·

but how is mass conserved??
isnt it converting into energy??

1
Ricky ·

But that energy factor only comes into play if there is at all a difference in mass of products as compared to mass of reactants . Since in the question , no energy factor is mentioned , so I guess you don ' t have to think about energy .

6
AKHIL ·

but that wud definitely be takin place
it is a radioactive reacn!!

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