3
msp
·2009-07-13 09:29:14
i think u wont need the proof MI.i dono the elegant proof.
3
msp
·2009-07-13 09:30:17
trying to do with binomial coeff's
11
rkrish
·2009-07-13 10:27:36
Contradiction is the best method.
Let n be composite.
So it can be written as n = x.y
2^{n}-1 = 2^{x.y}-1 = (2^{x}-1).(1+2^{x}+2^{2x}+...+2^{(y-1).x})
This makes 2^{n}-1 a composite no. whereas it is PRIME.
Hence, n has to be prime when 2n - 1 is prime (but the converse is not always true).
11
Devil
·2009-07-26 09:54:30
Just quoting an well-known result....
If ak-1 is a prime, then a=2, and k is a prime.....