9no byah i din do by trial and error :)
What is the largest positive integer n so that n! can be expressed as the product of n - 3 consecutive positive integers?
-
UP 0 DOWN 0 0 18
18 Answers
626! = 720 = 9x8x10
7! = !! (Dont know how to write it as product of 3 integers..(
I have no proof.. but I think 6!
9eureka
chk ur posts and finish of ur other open recent threads to a close pls
62oh sorry celestine
I started to take n! = product of 3 consecutive :(
62wow celestine.. 23.. how did you reach that far.. my mind stopped working beyond 6 ;)
9argument is based on logic not very convincing
u need to replace 4 terms by 1 term in n!
so replacing lower order to n+1 will give max n
ie 1.2.3.4 =24
11 as the product of n - 3 consecutive positive integers?
sir aapki counting mein 3x4x5 nahi aana chayiye kya??
please clear it!!!
11[11][11][11][11][11]
provide ur arguemeny
i am in sink with #2
give ur justification[1]
11the 2 options r
4 and 5
when we have 4 we have 4X3X2X1 =24
and incase of 5
we have 5!=5X4X3X2X1=5X4X3X2
