romanian mathematics masters 2009 paper

5 Answers

1
Ricky ·

Well , the first one is rather easy .

There is a well - known identity called Bezout ' s Lemma . It states that -

Suppose , d = G . C . D . ( y 1 , y 2 , y 3 , ...... , y n )

Then we can always find such integers ( x 1 , x 2 , x 3 , ...... , x n ) for which ,

But we have ,

Clearly , the R . H . S . of the equation is an integral number .

Hence , the problem .

39
Dr.House ·

nice one dude.. ur right

try the others too

1
Ricky ·

Actually , for Qs . 3 , the easiest proof is to find a way to prove that all the points O i lie on a Neuberg Cubic , and they do so as they are Isodynamic points on the circles of Apollonius built on each side of the four triangles . But that way is too complex , so I ' ll try to find out a simpler solution .

39
Dr.House ·

hm..

so u know about neuberg cubic..

where have you read about it?

1
Ricky ·

Well , I read that only in wikipedia :) Coz I coudn't find any book on it :(
Not that I have a sound knowledge about them , but still , this problem is based mainly on basic ideas ......

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