bitsat 5

IIT JEE Sample Questions › Optics questions › bitsat 5

A no. of tuning forks are arranged in the order of increasing frequency & any tw successive tuning foks produce 4 beatsper second,whn sounded together. If the last tuning fork has a frequency of octave higher than that of the first tuning fok & the frequecy of the first tuning fork is 256 Hz, then the no. of tuning forks is?

A)63
b)64
c)65
d)66

#Physics #Optics

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6 Answers

1

ANKIT MAHATO ·2009-05-02 23:47:50

65 is the ans

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13

deepanshu001 agarwal ·2009-05-03 00:37:22

ankit ...wat is meant by 1 octave higher...?

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1

ANKIT MAHATO ·2009-05-03 00:39:50

1 octave higher means .. double .. :)

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ANKIT MAHATO ·2009-05-03 00:40:03

now this sum is a cake walk :)

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13

deepanshu001 agarwal ·2009-05-03 00:42:01

yeah!

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1

sushrut17 ·2009-05-03 02:27:18

65

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