diffraction

i have a doubt that why does maximum appers at asinθ = (n + 1/2)λ ??
please yaar koi batao and why intensity decreases ... as n increases ..

11 Answers

1
ANKIT MAHATO ·

help !!

1
kamalendu ghosh ·

difraction mujhe bhi samajhme nahin aya thik se..but o adha adha karke kuch karta hain...NCERT mein hain na.....

9
Celestine preetham ·

its a ncert derivation

for diffraction maxima is when path diff is (n + 1/2)λ

1
ANKIT MAHATO ·

ncert mein ek baat galat dikha .. ya hum galat hai ..
a line says
one third intensity then 1/5 ..the n 1/7 ... yeh kaise laya !

1
ANKIT MAHATO ·

YELP !!

1
ANKIT MAHATO ·

YELP !!

1
ANKIT MAHATO ·

YELP !!

9
Celestine preetham ·

whats the prob jai ?

1
°ღ•๓яυΠ·

bcuz d path diffrnce is a integral multiple of wavelngth .......

ie the two waves interfre in phase ....... construtive interfrnce....
so intensity is maximum ......

9
Celestine preetham ·

ye thats for interference in youngs double slit exp

for diffraction in single slit exp eq reverse (see ncert )

1
ANKIT MAHATO ·

yaar my problem is that in ncert it is written when 3/2 lambda = a @ ,here @is an angle so 2/3 a @ = lambda .. so 2/3 of slit width cancels out in intensity and intensity is only due to 1/3 of slit ... now it is written that as n becomes more .. at maxima the intensities become 1/5 , 1/7 successively ... but how is this possible ... if 5/2 lambda = a @ , so 2/5 a @ = lambda so inensity sholud be 3/5 ..

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