difraction mujhe bhi samajhme nahin aya thik se..but o adha adha karke kuch karta hain...NCERT mein hain na.....
i have a doubt that why does maximum appers at asinθ = (n + 1/2)λ ??
please yaar koi batao and why intensity decreases ... as n increases ..
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11 Answers
its a ncert derivation
for diffraction maxima is when path diff is (n + 1/2)λ
ncert mein ek baat galat dikha .. ya hum galat hai ..
a line says
one third intensity then 1/5 ..the n 1/7 ... yeh kaise laya !
bcuz d path diffrnce is a integral multiple of wavelngth .......
ie the two waves interfre in phase ....... construtive interfrnce....
so intensity is maximum ......
ye thats for interference in youngs double slit exp
for diffraction in single slit exp eq reverse (see ncert )
yaar my problem is that in ncert it is written when 3/2 lambda = a @ ,here @is an angle so 2/3 a @ = lambda .. so 2/3 of slit width cancels out in intensity and intensity is only due to 1/3 of slit ... now it is written that as n becomes more .. at maxima the intensities become 1/5 , 1/7 successively ... but how is this possible ... if 5/2 lambda = a @ , so 2/5 a @ = lambda so inensity sholud be 3/5 ..