1/u+1/v=constant=1/f ---(i)
hence
du/u2=-dv/v2
find v using (i)
then ans = dv/dt=-v2/u2(du/dt)
AN OBJECT IS 20cm AWAY FROM A CONCAVE MIRROR WITH FOCAL LENGTH 15cm.IF THE OBJECT MOVES WITH THE SPEED OF 5m/s ALONG THE AXIS THEN WHAT IS THE SPEED OF THE IMAGE ?
please give the final answer along with steps
1/u+1/v=constant=1/f ---(i)
hence
du/u2=-dv/v2
find v using (i)
then ans = dv/dt=-v2/u2(du/dt)