ek aur

{(A.B)^c.(A.B)^c}^c

= {(A.B)^c}^c

= A.B

Eureka the rules of this topic are
A can take values 0 or 1

A'=1-A ... so if A is 0, A'=1... same if A is 1, A' = 0

again,

A.B is A and B. it is called the and operator. it is givenby straight line followed by a semi circle. It takes value 1 only if both A and B are 1. otherwise it takes value 0

A+B is or operator .. It take sthe value 1 if either A or B is 1. Otherwise it is zero.

A+A=A
A.A=A

(A')'=A

That is alll

Then you need to know truth tables :)

Which is again a 1 minute thing :)

Step by step explanation

The diagram gives the expression as {(A.B)^c.(A.B)^c}^c

using X.X=X where X= (A.B)^c
= {(A.B)^c}^c

using (X')'=X, we get
= A.B